Refactor interview parsing and answer splitting logic in Step4Report component
- Enhanced the `parseInterview` function to handle single-platform answers more effectively, ensuring default answers are set correctly. - Improved the answer splitting logic to robustly identify numbered sections, accommodating various formats and ensuring cleaner output. - Updated the handling of answer parts to remove unnecessary prefixes and trailing whitespace, enhancing overall readability.
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1 changed files with 49 additions and 27 deletions
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@ -727,8 +727,16 @@ const parseInterview = (text) => {
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interview.redditAnswer = redditMatch[1].trim()
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}
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// 如果没有明确分平台,整体作为回答
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if (!twitterMatch && !redditMatch) {
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// 如果只有一个平台的回答,将其作为主回答
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// 这样无论显示哪个平台都能有内容
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if (!twitterMatch && redditMatch) {
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// 只有 Reddit 回答,将其也设为 twitterAnswer 作为默认显示
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interview.twitterAnswer = interview.redditAnswer
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} else if (twitterMatch && !redditMatch) {
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// 只有 Twitter 回答,将其也设为 redditAnswer
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interview.redditAnswer = interview.twitterAnswer
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} else if (!twitterMatch && !redditMatch) {
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// 如果没有明确分平台,整体作为回答
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interview.twitterAnswer = answerText
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}
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}
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@ -954,37 +962,51 @@ const InterviewDisplay = {
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const splitAnswerByQuestions = (answerText, questionCount) => {
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if (!answerText || questionCount <= 0) return [answerText]
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// 尝试按编号分割 (如 "1." "2." 等)
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// 更健壮的分割逻辑:查找所有 "数字." 格式的编号位置
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// 支持格式:
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// - "1. \n内容" (数字+点+空格+换行+内容)
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// - "\n\n2. \n内容" (换行+数字+点+空格+换行+内容)
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// 使用更宽松的匹配:开头或换行后的数字+点+空白
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const numberPattern = /(?:^|[\r\n]+)(\d+)\.\s+/g
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const matches = []
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let match
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while ((match = numberPattern.exec(answerText)) !== null) {
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matches.push({
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num: parseInt(match[1]),
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index: match.index,
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fullMatch: match[0]
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})
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}
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// 如果没有找到编号或只找到一个,返回整体
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if (matches.length <= 1) {
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// 尝试移除开头的编号(格式:1. \n 或 1. )
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const cleaned = answerText.replace(/^\d+\.\s+/, '').trim()
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return [cleaned || answerText]
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}
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// 按编号提取各部分
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const parts = []
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let remaining = answerText
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for (let i = 0; i < matches.length; i++) {
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const current = matches[i]
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const next = matches[i + 1]
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for (let i = 1; i <= questionCount; i++) {
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const nextNum = i + 1
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// 查找下一个编号的位置
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const nextPattern = new RegExp(`\\n\\s*${nextNum}\\.\\s+|\\n\\s*${nextNum}、|\\n\\s*(${nextNum})|\\n\\s*\\(${nextNum}\\)`)
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const match = remaining.match(nextPattern)
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const startIdx = current.index + current.fullMatch.length
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const endIdx = next ? next.index : answerText.length
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if (match) {
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// 找到下一个编号,截取当前部分
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const splitIdx = match.index
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let currentPart = remaining.substring(0, splitIdx).trim()
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// 移除当前编号前缀
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currentPart = currentPart.replace(new RegExp(`^\\s*${i}\\.\\s*|^\\s*${i}、|^\\s*(${i})|^\\s*\\(${i}\\)`), '').trim()
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parts.push(currentPart)
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remaining = remaining.substring(splitIdx).trim()
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} else if (i === questionCount) {
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// 最后一个问题,取剩余所有内容
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let currentPart = remaining.replace(new RegExp(`^\\s*${i}\\.\\s*|^\\s*${i}、|^\\s*(${i})|^\\s*\\(${i}\\)`), '').trim()
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parts.push(currentPart)
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}
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let part = answerText.substring(startIdx, endIdx).trim()
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// 移除末尾可能的多余换行
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part = part.replace(/[\r\n]+$/, '').trim()
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parts.push(part)
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}
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// 如果分割失败,返回整体答案
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if (parts.length === 0 || parts.every(p => !p)) {
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return [answerText]
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// 如果分割成功且数量合理,返回分割结果
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if (parts.length > 0 && parts.some(p => p)) {
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return parts
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}
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return parts
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return [answerText]
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}
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// 获取某个问题对应的回答
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